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Canada irule
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PostPosted: Mon Mar 22, 2010 10:00 pm   Post subject: Reply with quote


I don't understand how you got πr²dh + 2πrhdr.

Here's what I did:

measured volume = (3.1415)x(10x10)x15
= 4712.25
max volume = (3.1415)x(11.2x11.2)x17.4
= 6856.81

The difference between the measured and the max is 2144.59.

So if the real volume is 6856.81, you were off by 31.27%. Why did you take the percent as fraction of the measured volume? Shouldn't it be a fraction of the volume with the highest difference?

What did I do wrong? Woah
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PostPosted: Mon Mar 22, 2010 10:42 pm   Post subject: Reply with quote


One seems sure: This is not
definitively Dark's thread...
Wink Grin Peace
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PostPosted: Mon Mar 22, 2010 10:53 pm   Post subject: Reply with quote


irule wrote:
I don't understand how you got πr²dh + 2πrhdr.

Here's what I did:

measured volume = (3.1415)x(10x10)x15
= 4712.25
max volume = (3.1415)x(11.2x11.2)x17.4
= 6856.81

The difference between the measured and the max is 2144.59.

So if the real volume is 6856.81, you were off by 31.27%. Why did you take the percent as fraction of the measured volume? Shouldn't it be a fraction of the volume with the highest difference?

What did I do wrong? Woah


First your value of pi is not precise enough causing a loss of accuracy. The value of pi is 3.141592654, using 3.14 would have been better. Or if you would have used 3.1416. I don't understand where you got the values 11.2 and 17.4.

We are also looking for the absolute error and the maximum possible relative error as a percent.


absolute error = ΔV (differentiate the equation for volume using product rule)

relative error = absolute error ÷ value of thing measured
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PostPosted: Mon Mar 22, 2010 10:58 pm   Post subject: Reply with quote


11.2 and 17.4 are the max radius and height given the possible error. I don't understand why you would need any other values since these give you the greatest difference in volume.
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PostPosted: Mon Mar 22, 2010 11:01 pm   Post subject: Reply with quote


irule wrote:
11.2 and 17.4 are the max radius and height given the possible error. I don't understand why you would need any other values since these give you the greatest difference in volume.


You should only use the given radius and height r = 10m & h = 15m. Then whatever measuring them has a limit of ±1.2m and ±2.4m. Any other values that are used will be incorrect. You see we are looking for the error because we have limits. If a computer can only measure ±1.2m as the radius before it starts producing incorrect results, 10m is going to fuck it up big time.

And that's the point of finding the solution(s) to this problem. To see just how wrong we/it is.
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PostPosted: Mon Mar 22, 2010 11:05 pm   Post subject: Reply with quote


What I'm saying is the range of possible values is 8.8-11.2 and 12.6-17.4. If you plug in the highest values you get a possible actual volume of 6856.
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PostPosted: Mon Mar 22, 2010 11:14 pm   Post subject: Reply with quote


irule wrote:
What I'm saying is the range of possible values is 8.8-11.2 and 12.6-17.4. If you plug in the highest values you get a possible actual volume of 6856.


I see what you're saying and that seems logical but that isn't the case with this problem. You can simply plug the given values in to the correct equations.

Check this out too.
http://www.phy.ilstu.edu/slh/Absolute%20Relative%20Error.pdf
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PostPosted: Mon Mar 22, 2010 11:25 pm   Post subject: Reply with quote


Can you explain how you got:

ΔV ≈ dV = (dπr²)
= πr²dh + hd(πr²)
= πr²dh + h2πrdr
= πr²dh + 2πrhdr
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PostPosted: Sun Mar 28, 2010 2:19 am   Post subject: Reply with quote


irule wrote:
Can you explain how you got:

ΔV ≈ dV = (dπr²)
= πr²dh + hd(πr²)
= πr²dh + h2πrdr
= πr²dh + 2πrhdr


I used the product rule of differentiation.
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PostPosted: Sun Mar 28, 2010 1:59 pm   Post subject: Reply with quote


Calculus needs to die. Neutral
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PostPosted: Sun Mar 28, 2010 2:08 pm   Post subject: Reply with quote


irule wrote:
Calculus needs to die. Neutral


LOL Mr. Green sadly a lot inventions wouldn´t be possible without it
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PostPosted: Sat Jun 19, 2010 4:33 am   Post subject: Reply with quote


Evil or Very Mad

Last edited by lunarstrain88 on Tue Jun 22, 2010 7:40 pm; edited 2 times in total
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PostPosted: Tue Jun 22, 2010 2:15 pm   Post subject: Reply with quote


Blowhard Very Happy.
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PostPosted: Tue Jun 22, 2010 8:16 pm   Post subject: Reply with quote


Dami wrote:
Blowhard Very Happy.

LOL LOL Peace
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PostPosted: Tue Jun 22, 2010 10:36 pm   Post subject: Reply with quote


Stuka_Kommandant wrote:
One seems sure: This is not
definitively Dark's thread...
Wink Grin Peace


You are correct, i refuse to use complicated mathematics unless needed or directed by a doctor.
OK!
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